The table shows the distribution of ages of a number of children in a school. If the mean of the distribution is 7, find the; (a) value of x, (b) standard deviation of their ages.
Age 3 4 5 6 7 8 9 10
No. of children 2 6 5 4 6 9 8 5
The table shows the distribution of ages of a number of children in a school. If the mean of the distribution is 7, find the;
(a) value of x, (b) standard deviation of their ages.
Solution & Explanation
Mean = (3×2 +4×6 + 5×5 + 6x + 7×6 + 8×9 + 9×8 + 10×5) ÷ (2 + 6 + 5 + x + 6 + 9 + 8 + 5)
7 = (291 + 6x) ÷ (41+x)
7(41+x) = 291 + 6x
287 + 7x = 291 + 6x
x = 4
(b)
Age(x in yrs) No.of child Fx2
3 2 18
4 6 96
5 5 125
6 4 144
7 6 294
8 9 576
9 8 648
10 5 500
Σf = 45 Σfx2 = 2401
Standard deviation = √196/45 = √4.3555
= 2.087