Mathematics 2021 Past Questions | WAEC
Study the following Mathematics past questions and answers for JAMB, WAEC NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.
- Correct, 0.00798516 to three significant figures
- A. 0109
- B. 0800
- C. 00799
- D. 0.008
Correct Option: Answer is C
First 2 non-zero digits from the start, ignore the zeros and count from digit 7
0.00798516
0.00798516 =0.00799 to 3 s.f,
2. Simplify (11two)2
- A. 1001two
- B. 1101two
- C. 101two
- D. 10001two
Correct Option: Answer is A
11
11
11
11
1001two
OR
CONVERT TO BASE 10
(11two)2 = (112) × (112)
= (1×21)+(1×20) × (1×21)+(1×20)
= (1×2+1×1)×(1×2+1×1)
= (2+1)×(2+1)
= 3 × 3
= 910
Convert to binary number
2 | 9 |
2 | 4 r1 |
2 | 2 r0 |
2 | 1 r0 |
| 0 r1 |
=10012
3. Solve = 2\(^\sqrt{2x+1}\) = 32
- A. 13
- B. 24
- C. 12
- D.11
Correct Option: Answer is C
2\(^\sqrt{2x+1}\) = 32 ;
2\(^\sqrt{2x+1}\) = 2\(^5\)
\(\sqrt{2x+1}\) = 5
2x+1 =52
2x+1=25; 2x =25-1
2x =24; x =12
4. If log102 =m and log103 =n, find log1024 In term of m and n.
- A. 3m+n
- B. m+3n
- C. 4mn
- D. 3mn
Correct Option: Answer is A
log1024 = log104 x 3x 2= log104+ log103+ log102
2log102 + log103+ log102
=2m + n + m
3m+n
5. Find the 5th term of the sequence 5, 10, 17, …….
- A. 22
- B. 24
- C. 36
- D. 26
Correct Option: Answer is D
Add odd number beginning from 3 to the next number
2
2 + 3 = 5
5 + 5 = 10
10 + 7 = 17
17 + 9 = 26
The fifth term = 26
6. If P = {-3<x<1} and Q ={-1<x<3}, where x is a real number find, P n Q.
- A. {-1<x<1}
- B. {-3<x<1}
- C. {-1<x<1}
- D. {-1<x<1}
Correct Option: Answer is D
7. Factorize 6pq-3rs-3ps + 6qr
- A. (3r-p) (2q + s)
- B. 3(p + r)(2q-s)
- C. 3(p – r)(2q-s)
- D. (3r-p)(s-2q)
Correct Option: Answer is B
6pq – 3rs – 3ps +6qr
=3(2pq – rs – 3ps +2qr)
=(2pq – rs – 3ps +2qr)=(2pq-ps)+(2qr-rs)
=(2pq-ps)+(2qr-rs)
Factor out p in the first and r in the second
p(2q-s)+r(2q-s); (2q-s)(p+r)= 3(p + r)(2q-s)
8. What number should be subtracted from the sum of 2 1/6 and 2 7/12 to give 3 ¼.
- A. 1/3
- B. 1 1/2
- C. 1 1/6
- D. 1/2
Correct Option: Answer is B
Let x be the number to be subtracted
2 1/6 +2 7/12 – x =3 1/4
=(13/6 + 31/12) – x = 13/4
=( 26 + 31 /12) -x =13/4; ( 57/12) – x =13/4
= 57/12 – x = 13/4; 57 -12x /12 = 13/4
= 4(57 – 12x)= 156; 228 – 48x = 156
-48x= 156 – 228;
X = 72/48; x = 3/2 = 1 1/2
9. Mensah is 5 years old and Joyce is thrice as old as Mensah. In how many years will Joyce be twice as old as Mensah?
- A. 3 years
- B. 10 years
- C. 5 years
- D. 15 years
Correct Option: Answer is C
Let J = Joyce’s age
and M = Mensah’s age
(1) J = 3*M = 3*5 = 15 (for current ages)
(2) 2(5 + x) = 15 + x (for future ages, unknown is “x” years for condition 2xM = J to be met)
Multiply left side both by 2:
10 + 2x = 15 + x
Subtract x from both sides:
10 + x = 15
Subtract 10 from both sides:
x = 5
10. If 16 x 2(x+1) = 4x x 8(1-x), find the value of x.
- A. -4
- B. 4
- C. 1
- D. -1
Correct Option: Answer is D
= 16 x 2(x+1) = 4x x 8(1-x)
= 24 x 2(x+1) =22x x 23(x+1)
= 4 + x + 1 = 2x + 3(1- x) = 4 + x + 1 = 2x + 3 – 3x
collect like terms
-> x – 2x + 3x = 3 – 1 – 4
-> 2x = -2
-> x = -1
11. The circumference of a circular track is 9 km. A cyclist rides round it a number of times and stops after covering a distance of 302km. How far is the cyclist from the starting point?
- A. 5km
- B. 6km
- C. 7km
- D. 3km
Correct Option: Answer is A
12. Simplify 2\(\sqrt{7}\) – \(\frac{14}{\sqrt{7}}\) + \(\frac{7}{\sqrt{21}}\)
- A. \(\frac{\sqrt{21}}{21}\)
- B. 7\(\frac{\sqrt{21}}{3}\)
- C. \(\frac{\sqrt{21}}{3}\)
- D.2\(\sqrt{3}\)
Correct Option: Answer is B
2√7- 14/√7 +7/√21
LCM is √21
13. If 4x +2y =16 and 6x – 2y = 4, find the value of (y-x)
- A. 8
- B. 2
- C. 4
- D. 6
Correct Option: Answer is B
4x +2y =16 x 6
6x – 2y = 4 x 4
24x + 12y = 96
24x – 8y = 16
20y = 80
Y=4
Substitute for y in eqn 1
4x + 2(4) =16; 4x +8 =16
4x =16 -8; 4x=8; x=2
Therefore, y-x=4-2=2
14. Given that R is directly proportional to L and inversely proportional to P, R=3 when L =9 and P=0.8, find R when L=15 and P =1.8
- A. 2.2
- B. 3.3
- C. 6.6
- D. 0.3
Correct Option: Answer is A
15.
In the diagram, angle ABC and angle BCD are right angles, angle BAD = t and angle EDF = 70o, find the value of t.
- A. 70\(^o\)
- B. 165\(^o\)
- C. 140\(^o\)
- D.110\(^o\)
Correct Option: Answer is D
opp angles are equal ∠CDE = 70°
Sum of interior angles in a quadrilateral = 360°
(90 + 90 + 70 + t)° = 360°
t° = 360° – 250°
t° = 110°