What volume of oxygen at s.t.p is required to burn completely 7.5 dm33 of methane according to the following equation? CH4 g + 202 g → CO2 g + H2Og

What volume of oxygen at s.t.p is required to burn completely 7.5 dm33 of methane according to the following equation?
CH4 g + 202 g → CO2 g + H2Og
A. 3.75 dm3
B. 7.59 dm3
C. 15.0 dm3
D. 30.0dm3

Correct Option: Answer is C
1 mole of methane reacts with 2 moles of oxygen
1 vol of methane reacts with 2 vol of oxygen
: 7.5 vol of methane will yield 15 vol of oxygen in dm3

0 0 votes
Article Rating

Solutions is incorrect? Kindly leave a feedback at the comment section

Subscribe
Notify of
guest

0 Comments
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x
Scroll to Top

Download UTME/JAMB Past Questions in PDF format

Get 30% Off with this promo code UZK5QNHC