The density of 400cm of palm oil was 0.9gcm-3 before frying. If the density of the oil was 0.6gm-3 after frying, assuming no loss of oil due to spilling, its new volume was?

2. The density of 400cm of palm oil was 0.9gcm-3 before frying. If the density of the oil was 0.6gm-3 after frying, assuming no loss of oil due to spilling, its new volume was?
A. 1360cm3
B. 600cm3
C. 240cm3
D. 8000m3

Correct Option: Answer is B

Density=mass/volume
⇒ 0.9gcm−3=mass/400cm3=360g
without any loss in the frying process, we have
0.6gcm−3=360gv
v=360g/0.6gcm−3=600cm3

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