Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.

a mechanical wave that require a material medium
3. Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.
A. 18.57NC−1
B. 53.06N C−1
C. 2.28NC−1
D. 0.80NC−1

Correct Option: Answer is A

Electric Field Intensity (E) = v/d

= (potential difference)/distance

= (6.5v )/35cm

= (6.5v )/(35 x 10-2) = 18.57NC−1

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