A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms−2]

A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms−2]
A. 0.04m
B. 0.12m
C. 0.01m
D. 0.08m

Correct Option: Answer is D

From Hoke’s Law, F = ke, K = Constant of Force

For the first case, Force = mg,

= 0.8 × 10 = 8N

∴ 8 = k × 0.04

k = 8/0.04

= 200N/m

Since K is constant

For the second case, F = ke

F = 200 × e

∴ e = F/200

= 16/200 = 0.08m

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