A man swung an object of mass 2 kg in a circular path with a rope 1.2 m long. If the object was swung at 120 rev/min, find the tension in the rope.

A man swung an object of mass 2 kg in a circular path with a rope 1.2 m long. If the object was swung at 120 rev/min, find the tension in the rope.
A. 400
B. 288
C. 240
D. 379

Correct Option: Answer is D
m=2kg, r=1.2m, f=120rev/min ; T=?

f= 120rev/1min x 1min/60s = 2revs

w=2πf= 2×π×2= 4πrads

T= mv2r, but v = wr

⇒ T = (m)(wr)2/ r

⇒ T = mw2r

= T = 2× (4π)^2 × 1.2

T = 379N ( to 3 s.f)

0 0 votes
Article Rating

Solutions is incorrect? Kindly leave a feedback at the comment section

Subscribe
Notify of
guest

0 Comments
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x
Scroll to Top
Scroll to Top

Download UTME/JAMB Past Questions in PDF format

Get 30% Off with this promo code UZK5QNHC