## A lorry accelerates uniformly in a straight line with acceleration of 4ms−2 and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?

A lorry accelerates uniformly in a straight line with acceleration of 4ms−2 and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?
A. 650
B. 900
C. 800
D. 250

To solve this problem, we can use the equations of motion for uniformly accelerated motion. We know the initial acceleration (a = 4 m/s^2), the initial distance (d1 = 250 m), and the initial time (t1 = 10 s). We need to find the final distance (d2) after another 10 seconds (t2 = 10 s).
There are two possible approaches:
Method 1: Using Velocity formula
1. Find the final velocity (v2) after the first 10 seconds: v2 = v1 + at1 Where v1 is the initial velocity (unknown). Since the truck starts from rest, v1 = 0. Therefore, v2 = 0 + 4 * 10 = 40 m/s
2. Now, use the distance-velocity-time relationship to find the final distance (d2): d2 = d1 + v2 * t2 d2 = 250 + 40 * 10 = 650 m
Therefore, the lorry will travel 650 meters in the next 10 seconds.
Method 2: Using Distance formula
1. Directly use the distance-acceleration-time relationship: d2 = d1 + 1/2 * a * (t1^2 + 2 * t1 * t2 + t2^2) d2 = 250 + 1/2 * 4 * (10^2 + 2 * 10 * 10 + 10^2) d2 = 250 + 2 * 4 * 100 = 650 m

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