A lorry accelerates uniformly in a straight line with acceleration of 4ms−2 and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?

A. 650

B. 900

C. 800

D. 250

Correct Option: Answer is A

To solve this problem, we can use the equations of motion for uniformly accelerated motion. We know the initial acceleration (a = 4 m/s^2), the initial distance (d1 = 250 m), and the initial time (t1 = 10 s). We need to find the final distance (d2) after another 10 seconds (t2 = 10 s).

There are two possible approaches:

Method 1: Using Velocity formula

1. Find the final velocity (v2) after the first 10 seconds: v2 = v1 + at1 Where v1 is the initial velocity (unknown). Since the truck starts from rest, v1 = 0. Therefore, v2 = 0 + 4 * 10 = 40 m/s

2. Now, use the distance-velocity-time relationship to find the final distance (d2): d2 = d1 + v2 * t2 d2 = 250 + 40 * 10 = 650 m

Therefore, the lorry will travel 650 meters in the next 10 seconds.

Method 2: Using Distance formula

1. Directly use the distance-acceleration-time relationship: d2 = d1 + 1/2 * a * (t1^2 + 2 * t1 * t2 + t2^2) d2 = 250 + 1/2 * 4 * (10^2 + 2 * 10 * 10 + 10^2) d2 = 250 + 2 * 4 * 100 = 650 m