A 200 kg load is raised using a 110 m long lever as shown in the diagram above. The load is 10m from the pivot P. If the efficiency of the lever is 80%, find the effort E required to lift the load.

A 200 kg load is raised using a 110 m long lever as shown in the diagram above. The load is 10m from the pivot P. If the efficiency of the lever is 80%, find the effort E required to lift the load.

[Take g = 10ms-2]
A. 250
B. 300
C. 450
D. 200
Correct Option: Answer is A
ε= 80%, L=200× 10 = 2000N, dL��=10m

dE��= 110-10 = 100m, E=?

ε = workdoneontheload/workdonebytheeffort x 100%

⇒ work done on load = 2000 ×10 =20,000 j

⇒ work done by effort = E × 100 = 100E

80 = 20,000/100E × 100%

80 = 20,000/E

E = 20,000/80

E = 250N

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