Three consecutive terms of a geometric progression are given as n – 2, n and n + 3. Find the common ratio

Three consecutive terms of a geometric progression are given as n – 2, n and n + 3. Find the common ratio
A. 3/2
B. 2/3
C. 1/2
D. 1/4

Correct Option: Answer is A
Solution:
=n/(n-2) = (n+3)/n
n2 = (n + 3) (n – 2)
n2 = n2 + n – 6
n2 + n – 6 – n2 = 0
n – 6 = 0
n = 6
Common ratio: n/(n-2)= 6/(6-2) = 3/2

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