The sum of the interior angle of pentagon is 6x + 6y. Find y in terms of x.

The sum of the interior angle of pentagon is 6x + 6y. Find y in terms of x.
A. y = 6 – x
B. y = 90 – x
C. y = 120 – x
D. y = 150 – x

Correct Option: Answer is B
Solution:

Sum of interior angles = (2n – 4) 90o
For pentagon, n = 5
Sum of interior angles = 6 x 90o = 540o
6x + 6y = 540o
6(x + y) = 540o
x + y = 540/6 = 90o
y = 90o
y = 90 – x

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