The nth term of a sequence is given by 2²n–1. Find the sum of the first four terms.

The nth term of a sequence is given by 2²n–1. Find the sum of the first four terms.
A. 74
B. 32
C. 42
D.170

Correct Option: Answer is D

Solution:

Tn=2^(2n-1)
T1=2^(2(1)-1)
= 2
T2=2^(2(2)-1)
= 8
T3=2^(2(3)-1)
= 32
T4=2^(2(4)-1)
= 128
T1+T2+T3+T4=2+8+32+128
= 170

0 0 votes
Article Rating
Subscribe
Notify of
guest

0 Comments
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x
Scroll to Top