Mathematics 2018 Past Questions | JAMB
Study the following Mathematics past questions and answers for JAMB, WAEC NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.
11. Convert 0.04945 to two significant figures
- A. 0.040
- B. 0.049
- C. 0.050
- D. 0.49
Correct Option: Answer is B
12. The probabilities that John and James pass an examination are \(\frac {3}{4}\)and \(\frac {3}{5}\) respectively. Find the probability of both boys failing the examination.
- A.\(\frac {1}{10}\)
- B.\(\frac {2}{10}\)
- C.\(\frac {9}{20}\)
- D.\(\frac {11}{20}\)
Correct Option: Answer is D
Pr(both John and James passed)
= \(\frac {3}{4}\) x \(\frac {3}{5}\)
= \(\frac {9}{20}\)
Pr(john and james failed)= 1- Pr(john and james passed)
= 1 – \(\frac {9}{20}\)
= \(\frac {11}{20}\)
13. An arc of a circle of radius 14cm subtends angle 300° at the centre. Find the perimeter of the sector formed by the arc (take π = 22/)
- A. 14.67cm
- B. 42.67cm
- C. 101.33cm
- D. 513.33cm
Correct Option: Answer is C
Perimeter of a sector =
Arc Length + Radius + Radius;
π= 22/7
∴ 300/360 x 2 x π x 14 + (14 + 14)
= 101.33cm
14. Simplify \(\frac {25^{\frac{2}{3}} \div 25^{\frac{1}{6}}} {(\frac{1}{5})^{\frac{7}{6}} \div (\frac{1}{5})^{\frac{1}{6}}}\)
- A.25
- B\(\frac{1}{5}\)
- C.1
- C.\(\frac{1}{25}\)
Correct Option: Answer is A
\(\frac {25^{\frac{2}{3}} \div 25^{\frac{1}{6}}} {(\frac{1}{5})^{\frac{7}{6}} \div (\frac{1}{5})^{\frac{1}{6}}}\)
= \(\frac{25^{\frac{2}{3} – \frac{1}{6}}}{(\frac{1}{5})^{\frac{7}{6} – \frac{1}{6}}}\)
= \(\frac{25^{\frac{1}{2}}}{(\frac{1}{5})}\)
= \(5 \div \frac{1}{5}\)
= 25
15. \(\text{P} = \left[\frac{\mathrm{Q(R – T)}}{15}\right]^\frac{1}{3}\)
Make T the subject of the relation.
- A. T = \(\frac{R + P3}{15Q}\)
- B. T = \(\frac{R – 15P^3}{Q}\)
- C. T =R – \(\frac{15P^3}{Q}\)
- D. T = \(\frac{15R + Q}{P^3}\)
Correct Option: Answer is C
16. What is the place value of 9 in the number 3.0492?
- A. \(\frac{9}{10000}\)
- B. \(\frac{9}{1000}\)
- C. \(\frac{9}{100}\)
- D. \(\frac{9}{10}\)
Correct Option: Answer is B
17. If the simple interest on a sum of money invested at 3% per annum for 2 years is N123,
find the principal.
- A. N676.50
- B. N820
- C. N1,640
- D. N4,920
Correct Option: Answer is C
SI = P T R
SI = 123 (Given)
T = 2.5 yrs
R = 3% or 0.03
∴ 123 = P x 2.5 x 0.03
P =123/0.075
∴ P = N1,640
18. A machine valued at N20,000 depreciates by 10% every year. What will be the value of the machine at the end of two years?
- A. N16,200
- B. N14,200
- C. N12,000
- D. N8,000
Correct Option: Answer is A
Since it depreciates by 10% At the end of first year, its value = 90% of 20000
= \(\frac{90}{100}\) x 20000 =18000
At the end of second year, its value = 90% of 18000
= \(\frac{90}{100}\) x 18000 = ₦16,200
19. The table shown gives the marks scored by a group of student in a test. Use the table to answer the question given.
Mark | 0 | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 2 | 7 | 5 | 4 | 3 |
What is the median mark?
- A. 1
- B. 2
- C. 3
- D. 4
Correct Option: Answer is C
20. The table shown gives the marks scored by a group of student in a test. Use the table to answer the question given.
Mark | 0 | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 2 | 7 | 5 | 4 | 3 |
What is the probability of selecting a student from the group that scored 2 or 3
- A.\(\frac{1}{11}\)
- B.\(\frac{5}{22}\)
- C.\(\frac{7}{22}\)
- D.\(\frac{6}{11}\)