Mathematics 2018 Past Questions | JAMB
Study the following Mathematics past questions and answers for JAMB, WAEC NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.
In a class of 40 students, 32 offer Mathematics, 24 offer Physics and 4 offer neither Mathematics nor Physics. How many offer both Mathematics and Physics?
- A. 4
- B. 8
- C. 16
- D. 20
Correct Option: Answer is D
Let the number of people that offer both Mathematics and Physics = y
Then, (32−y)+y+(24−y)+4=40
60−y=40⟹y=20
20 students offer both Mathematics and Physics.
2. Find the values of x for which (x + 2) / 4 -(2x -3)/3 < 4
- A. x < 8
- B. x > -6
- C. x < 4
- D. x > -3
Correct Option: Answer is B
\(\frac {x+2}{4}\) – \(\frac{2x – 3}{3} < 4\)
\(\frac{3(x + 2) – 4(2x – 3)}{12} < 4\)
\(3x + 6 – 8x + 12 < 48 \)
\(18 – 5x < 48 \implies -5x < 30\)
\(\therefore x > -6\)
3.
The pie chart shows the monthly expenditure of a public servant. The monthly expenditure on housing is twice that of school fees. How much does the worker spend on housing if his monthly income is N7200?
- A. 1000
- B. 2000
- C. 3000
- D. 4000
Correct Option: Answer is B
Let the angle for school fees = x°
Then Housing = 2x°
120° + 90° + x° + 2x° = 360°
3x° = 150° , x° = 50°.
Amount spent on housing = 100/360×7200
= N2000.
4. A trader realises 10x – x\(^2\) Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?
- A. 7
- B. 6
- C. 5
- D. 4
Correct Option: Answer is C
Profit (P) = 10\(_x\) − \(_x\)2
Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0
i.e. \(\frac{dp}{dx}\) = 0
\(\frac{dp}{dx}\) = 10 – 2x = 0
10 = 2x
Then x = \(\frac{10}{2}\) = 5
Answer is C
5. If y = 23\(_{5}\) + 101\(_{3}\) , find y, leaving your answer in base two
- A. 1110
- B. 10111
- C. 11101
- D. 111100
Correct Option: Answer is B
y = 23\(_{five}\) + 101\(_{three}\)
23\(_{five}\) = \(2 \times 5^1 + 3 \times 5^0\)
= 13\(_{ten}\)
101\(_{three}\) = \(1 \times 3^2 + 0 \times 3^1 + 1 \times 3^0\)
= 10\(_{ten}\)
y\(_{ten}\) = 13\(_{ten}\) + 10\(_{ten}\)
= 23\(_{ten}\)
= 10111\(_{two}\)
6.
Find the value of x in the diagram
- A. 10°
- B. 28°
- C. 36°
- D. 40°
Correct Option: Answer is D
The diagram shows angles at a point, the total angle at a point is 360
x – 10 + 4x – 50 + 2x + 3x + 20 = 360
10x – 40 = 360
10x = 360 + 40
10x = 400
x = 400/10
x = 40
7. Solve for t in the equation \(\frac{3}{4}\)t + \(\frac{1}{3}\)(21 – t) = 11
- A. \(\frac{9}{13}\)
- B. \(\frac{7}{13}\)
- C. 5
- D. 9\(\frac{3}{5}\)
Correct Option: Answer is D
\(\frac{3}{4}\) t + \(\frac{1}{3}\) (21 – t) = 11
Multiply through by the LCM of 4 and 3 which is 12
12 x(\(\frac{3}{4}\) t) + 12 x (\(\frac{1}{3}\) (21 – t)) = (11 x 12)
9t + 4(21 – t) = 132
9t + 84 – 4t = 132
5t + 84 = 132
5t = 132 – 84 = 48
t = \(\frac{48}{5}\)
t = 9 \(\frac{3}{5}\)
Answer is D
8. A school girl spends \(\frac{1}{4}\) of her pocket money on books and \(\frac{1}{3}\) on dress. What fraction remains?
- A. \(\frac{5}{6}\)
- B. \(\frac{7}{12}\)
- C. \(\frac{5}{12}\)
- D. \(\frac{1}{6}\)
Correct Option: Answer is C
9. If \(\frac{x}{a + 1}\) + \(\frac{y}{b}\) = 1. Make y the subject of the relation.
- A. \(\frac{b(a + 1 – x)}{a + 1}\)
- B. \(\frac{a + 1}{b(a – x + 1)}\)
- C.\(\frac{a(b – x + 1)}{b + 1}\)
- D. \(\frac{b}{a(b – x + 1)}\)
Correct Option: Answer is A
10. Calculate the total surface area of a cupboard which measures 12cm by 10cm by 8cm
- A. 1920cm²
- B. 592cm²
- C. 296cm²
- D. 148cm²
Correct Option: Answer is B
Total surface area of a cupboard is given by the equation A = 2(lb + bh + lh) L = 12, b = 10, h = 8
A = 2((12 x 10) + (10 x 8) + (12 x 8))
A = 2(120 + 80 + 96)
A = 2 x 296
A = 592cm2