Mathematics 2017 Past Questions | WAEC
Study the following Mathematics past questions and answers for JAMB, WAEC NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.
31. Given that t = \(2 ^{-x}\), find \(2 ^{x + 1}\) in terms of t.
- A. \(\frac{2}{t}\)
- B. \(\frac{t}{2}\)
- C. \(\frac{1}{2t}\)
- D. t
Correct Option: Answer is A
32. Two bottles are drawn with replacement from a crate containing 8 coke, 12 and 4 sprite bottles. What is the probability that the first is coke and the second is not coke?
- A. \(\frac{1}{12}\)
- B. \(\frac{1}{6}\)
- C. \(\frac{2}{9}\)
- D. \(\frac{3}{8}\)
Correct Option: Answer is C
33. If the simple interest on a certain amount of money saved in a bank for 5 years at 212% annum is N500.00, calculate the total amount due after 6 years at the same rate
- A. N2,500.00
- B. N2,600.00
- C. N4,500.00
- D. N4,600.00
Correct Option: Answer is D
34. Calculate the variance of 2, 3, 3, 4, 5, 5, 5, 7, 7 and 9
- A. 2.2
- B. 3.4
- D. 4.0
- D. 4.2
Correct Option: Answer is D
35. A circular pond of radius 4m has a path of width 2.5m round it. Find, correct to two decimal places, the area of the path. [Take22/7]
- A. 7.83m2
- B. 32.29m2
- C. 50.29m2
- D. 82.50m2
Correct Option: Answer is D
36.
Fig. 1 and Fig. 2 are the addition and multiplication tables respectively in modulo 5. Use these tables to solve the equation (n ⊕4)
- A. 1
- B. 2
- C. 3
- D. 4
Correct Option: Answer is C
(n 4) 3 = 0 (mod 5)
(3 4) 3
12 3 = 15 (mod 5)
(5 x 3 + 0) = 0 (mod 5)
37.
The diagram shows a circle centre O. if <STR = 29 and <RST = 450, calculate the value of <STO
- A. 12º
- B. 15º
- C. 29º
- D. 34º
Correct Option: Answer is A
SRT = 180 – (46 + 29) sum of < s in a
= 180 – 75
= 105
SOT = 2 x 46 < at the centre is twice all the circle = 92
RTO = 180 – (96 + 43)
= 41
STO = 41 – 29
= 12º
38.
In the diagram, XY is a straight line. <POX = <POQ and <ROY = <QOR. Find the value of <POQ + <ROY.
- A. 60º
- B. 90º
- C. 100º
- D. 120º
Correct Option: Answer is C
<POX = <POQ; <ROY = QOR
2 <POQ + 2 <ROY = 180
2(<POQ = <ROY) = 180
<POQ + <ROY = 90
39
The diagram shows a circle O. If < ZYW = 33º
, find < ZWX
- A. 33º
- B. 57º
- C. 90º
- D. 100º
Correct Option: Answer is C
In ZY = 90º < subtends In a semi O
ZWY = 180 – (90 + 33)
= 57
ZWX = 57 + 33 = 90º
40.
In the diagram, PQ and PS are tangents to the circle O. If PSQ = m, <SPQ = n and <SQR = 33º, find the value of (m + n)
- A. 103º
- B. 123º
- C. 133º
- D. 143º
Correct Option: Answer is B
< SQP = 180 – (90 + 33) < on a straight line
= 180 – (123)
= 57º
Therefore, (m + n) = 123º