Mathematics 2017 Past Questions | WAEC
Study the following Mathematics past questions and answers for JAMB, WAEC NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.
Express 0.0000407, correct to 2 significant figures
- A. 0.0
- B. 0.00004
- C. 0.000041
- D. 0.0000407
Correct Option: Answer is C
2. If x varies inversely as y and y varies directly as z, what is the relationship between x and z?
- A. x \(\alpha\) z
- B. x \(\alpha\) \(\frac{1}{z}\)
- C. a \(\alpha\) z\(^2\)
- D. x \(\alpha\) \(\frac{1}{z^2}\)
Correct Option: Answer is B
\(x \propto \frac{1}{y}\), y \(\propto\) z
x = \(\frac{k}{y}\)
y = mz
Since y = mz,
x = \(\frac{k}{mz}\), where k and m are constants. Hence,
x \(\propto\) \(\frac{1}{z}\)
3. Evaluate \(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} – 5 \frac{1}{3}}\)
- A. \(\frac{14}{15}\)
- B. \(\frac{13}{15}\)
- C. \(\frac{4}{5}\)
- D. \(\frac{11}{15}\)
Correct Option: Answer is B
\(\frac{3\frac{1}{4} \times 1\frac{3}{5}}{11\frac{1}{3} – 5 \frac{1}{3}}\) = \(\frac{\frac{26}{5}}{\frac{18}{3}}\) = \(\frac{26}{5} \div \frac{18}{3}\)
= \(\frac{13}{15}\)
4. The ages of Tunde and Ola are in the ratio 1:2. If the ratio of Ola’s age to Musa’s age is 4:5, what is the ratio of Tunde’s age to Musa’s age?
- A. 1 : 4
- B. 1 : 5
- C. 2 : 5
- D. 5 : 2
Correct Option: Answer is C
Tunde: Ola \(\to\) 1 : 2 ; Ola; Musa \(\to\) 4 : 5
\(\frac{1}{2}\) x \(\frac{4}{5}\)
= \(\frac{2}{5}\)
5. If M = {x : 3 ≤ x < 8} and N = {x : 8 < x ≤ 12}, which of the following is true?
i. 8 ∈ M ∩ N
ii. 8 ∈ M N
iii. M ∩ N = ∅
- A. iii only
- B. i and ii
- C. ii and iii only
- D. i, ii and iii
Correct Option: Answer is A
M = {3, 4, 5, 6, 7,}, N = {9, 10, 11, 12}
6. Given that a = log 7 and b = 2, express log 35 in terms of a and b.
- A. a + b + 1
- B. ab – 1
- C. a – b + 1
- D. b – a + 1
Correct Option: Answer is C
Explanation
\(\frac{\log 7 \times \log 10}{\log 2}\)
log 7 x log 10 \(\div\) log 2
a + 1 – b
a – b + 1
7. If x = 2/3 and y = – 6, evaluate xy – y/x
- A. 0
- B. 5
- C. 8
- D. 9
Correct Option: Answer is B
x = \(\frac{2}{3}\) and y = – 6
xy – \(\frac{y}{x}\)
\(\frac{2}{3} – (6)^2 – (-6) \div \frac{2}{3}\)
= -4 – (6) x \(\frac{3}{2}\)
= -4 – (-6) x \(\frac{3}{2}\)
= -4 – (-9)
= -4 + 9
= 5
8. Solve the equation: 1/5x + 1/x= 3
- A. 1/5
- B. 2/5
- C. 3/5
- D. 4/5
Correct Option: Answer is B
\(\frac{1}{5x} + \frac{1}{x}\)= 3
\(\frac{1 + 5}{5x}\) = 3
6 = 15x
x = \(\frac{6}{15}\)
= \(\frac{2}{5}\)
9. A sum of N18,100 was shared among 5 boys and 4 girls with each boy taking N20.00 more than each girl. Find a boy’s share.
- A. N1,820.00
- B. 2,000.00
- C. N2,020.00
- D. N2,040.00
Correct Option: Answer is C
Let a girl’s share = x + 20
4x + 5(x + 20) = 18,100
4x + 5x + 100 = 18,100
9x + 100 = 18,100
9x = 18,000
x = 18,000/9
x = 2,000
Each boy gets N(2,000 + 20)
= N2,020.
10. One factor of 7x²+3x−10 is
- A. 7x + 5
- B. x – 2
- C. 7x – 2
- D. x – 5
Correct Option: Answer is C