Mathematics 2021 Past Questions | WAEC
Study the following Mathematics past questions and answers for JAMB, WAEC NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.
31. A trapezium of sides 10cm and 21cm and height 8cm is inscribed in a circle of radius 7cm, calculate the area of the region not covered by the trapezium (take π=22/7)
- A. 84cm2
- B. 80cm2
- C. 30cm2
- D. 94cm2
Correct Option: Answer is C
Area of circle – Area of Trapezium
Area of Circle = A = π r²
Area of Trapezium = ½ × (a + b) × h
22/7 x 7 x 7 – ½ × (10 + 21) × 8
= 154 – 124 =30cm2
32. Find, correct to two decimal places, the mean of 1 1/2, 2 2/3, 3 3/4, 4 4/5 and 5 5/6
- A. 3.71
- B. 3.70
- C. 3.69
- D. 3.72
Correct Option: Answer is B
1.5+2.67+3.75+4.8+5.58 =18.3/5 =3.66 =3.70 to 2.d.p
33. A cyclist moved at a speed of X km/h for 2 He then increased his speed by 2 km/h for the next 3 hours. If the total distance covered is 36 km, calculate his initial speed, X
- A. 12km/h
- B. 3km/h
- C. 3km/h
- D.6km/h
Correct Option: Answer is C
2\(^\sqrt{2x+1}\) = 32 ;
2\(^\sqrt{2x+1}\) = 2\(^5\)
\(\sqrt{2x+1}\) = 5
2x+1 =52
2x+1=25; 2x =25-1
2x =24; x =12
34. Find the value of (x+y) in the diagram
- A. 215o
- B. 70o
- C. 135o
- D. 145o
Correct Option: Answer is D
= 110 +35 =145o
35. In the diagram, MP is a tangent to the circle NQR, /PNQ= 64o and |RQ| = |RN find the angle marked x.
- A. 22
- B. 24
- C. 36
- D. 26
Correct Option: Answer is D
36. find the first quartile of 8, 7, 9, 11, 8 7, 9, 6 and 8
- A. 8.5
- B. 7.0
- C. 7.5
- D. 8.0
Correct Option: Answer is B
6,7,7,7,8,8,8,9,9,11
Q1 =7 + 7= 14/2 =7
37. In the diagram, PQRS is a circle, find the value of x.
- A. 50o
- B. 50o
- C. 80o
- D. 50o
Correct Option: Answer is
38. A cone has a base radius of 8cm and height 11cm. calculate, correct to two decimal places, the curved surface area. Take π=22/7
- A. 341.98cm2
- B. 276.57cm2
- C. 201.14cm2
- D. 477.71cm2
Correct Option: Answer is B
Curve surface area = πrl
=22/7 x 8 x 11 = 276.57cm2
39. Given that sin x =3/5, 0<x<90o, evaluate (tan x +2 cos x)
- A.2 11/20
- B. 2 7/20
- C. 11/20
- D. 1/20
Correct Option: Answer is B
Sinx = 3/5; cosx =4/5; tanx = ¾
Therefore, (tan x +2 cos x)
= ¾ + 2 x 4/5 = ¾ + 8/5 = 15+32/20 =47/20 = 2 7/20
40. In the diagram, EC is a diameter of the circle ABCDE. If angle ABC= 158o find angle ADE.
- A. 112o
- B. 90o
- C. 68o
- D. 22o
Correct Option: Answer is C
41.
Height ()cm | 160 | 161 | 162 | 163 | 164 | 165 |
No of Player | 4 | 6 | 3 | 7 | 8 | 9 |
The table shows the heights of thirty seven players of a basketball team. Calculate, correct to one decimal place the mean height of the player
- A. 163.0
- B. 162
- C.0 160.5
- D. 165.0
Correct Option: Answer is A
Height (x) | No of Players (f) | fx |
160 | 4 | 640 |
161 | 6 | 966 |
162 | 3 | 486 |
163 | 7 | 1141 |
164 | 8 | 1312 |
165 | 9 | 1485 |
| 37 | 6030 |
Mean height = 6030/37 =163 2.d,p
42. XY is a line segment with the coordinates X(-8,-12) and Y(p,q). if the midpoint of XY is (-4, -2) find the coordinates of Y
- A. (-6,-10)
- B. (0,8)
- C. (4,10)
- D.(0,4)
Correct Option: Answer is B
x1= -8; x2 = p, y1= -12; y2 =q
midpoint = x1 + x2/2 ; y1 + y2/2
-4= -8+p/2; -2 = -12+q/2
-8= -8 + p; p =0
-4= -12 + q; q= 8
Therefore, coordinate of Y is (0, 8)
43. Five hundred tickets were sold for a concert. Tickets for adults and children were sold at $4.50 and $3.00 respectively. If the total receipts for the concert was $ 1,987 50, how many tickets for adults were sold?
- A. 325
- B. 235
- C. 175
- D. 400
Correct Option: Answer is A
Adult = a; Children =c
Total receipts sold = 4.5a + 3c =1987.5
Total ticket = a + c = 500
4.5a + 3c =1987.5 x 1
a + c = 500 x 4.5
4.5a + 3c =1987.5
4.5a + 4.5c = 2250
1.5c = 262.5/1.5
C = =175 ticket sold for children, while 500 -175= 325 ticket sold for Adults
44. The distance (d) between two villages is more than 18 km but not more than 23 km Which of these inequalities represents the statement?
- A. 18≤d≤23
- B. 18<d<23
- C. 18≤d<23
- D. 18<d≤23
Correct Option: Answer is B
45. The pie chart represents the distribution of fruits on display in a shop. If there are 60 apples on display, how many oranges are there?
- A. 80
- B. 270
- C. 120
- D.90
Correct Option: Answer is D
Let x represents total of fruit in display
Apples has 60 apples
=80/360 x X =60; 80/360 = 60; x =270
So orange = 120/360 x 270 =90