Mathematics 2019 Past Questions | WAEC

Study the following Mathematics past questions and answers for JAMBWAEC  NECO and Post-JAMB. Get prepared with official past questions and answers for upcoming examinations.

  1. Evaluate and correct to two decimal places, 75.0785 – 34.624 + 9.83 
  • A. 30.60
  • B. 50.29
  • C. 50.28
  • D. 30.62

2. If x = {x : x < 7} and Y = {y : y is a factor of 24} are subsets of μ= {1, 2, 3…10} find X ∩ Y

  • A. {2, 3, 4, 6}
  • B. {1, 2, 3, 4, 6}
  • C. {2, 3, 4, 6, 8}
  • D. {1, 2, 3, 4, 6, 8}

3.  Simplify  [(\(\frac{16}{9}\))\(^{\frac{-3}{2}}\) x 16\(^{\frac{-3}{2}}\)]\(^{\frac{1}{3}}\)

  • A. \(\frac{3}{4}\)
  • B. \(\frac{9}{16}\)
  • C. \(\frac{3}{8}\)
  • D. \(\frac{1}{4}\)
4. 
Express 1 + 2 log10\(^3\) in the form log10\(^9\)
  • A. log10\(^{90}\)
  • B. log10\(^{19}\)
  • C. log10\(^{9}\)
  • D. log10\(^{6}\)

5.  If 101two+ 12y = 3.3five. Find the value of y

  • A. 8
  • B. 7
  • C. 6
  • D. 5

6.   An amount of N550,000.00 was realized when a principal, x was saved at 2% simple interest for 5 years. Find the value of x

  • A. N470,000.00
  • B. N480,000.00
  • C. N490,000.00
  • D. N500,000.00

7.  Given that \(\frac{\sqrt{3} + \sqrt{5}}{\sqrt{5}}\) 

= x + y\(\sqrt{15}\), find the value of (x + y) 

  • A. 1\(\frac{3}{5}\)
  • B. 1\(\frac{2}{5}\)
  • C. 1\(\frac{1}{5}\)
  • D. \(\frac{1}{5}\)

8.  If x = 3 and y = -1, evaluate 2(x\(^2\) – y\(^3\))

  • A. 24
  • B. 22
  • C. 20
  • D. 16

9.  Solve 3x – 2y = 10 and x + 3y = 7 simultaneously

  • A. x = -4 and y = 1
  • B. x = -1 and y = -4
  • C. x = 1 and y = 4
  • D. x = 4 and y = 1

10. The implication x →y is equivalent to 

  • A. ~ y → ~ x
  • B. y → ~ x
  • C. ~ x → ~ y
  • D. y → x

11.  The first term of a geometric progression (G.P) is 3 and the 5th term is 48. Find the common ratio. 

  • A. 2
  • B. 4
  • C. 8
  • D. 16

12.   Solve \(\frac{1}{3}\)(5 – 3x) < \(\frac{2}{5}\)(3 – x)

  • A. x > \(\frac{7}{22}\)
  • B. x < \(\frac{7}{22}\)
  • C. x > \(\frac{-7}{27}\)
  • D. x < \(\frac{-7}{27}\)

13.   Make m the subject of the relation k = \(\frac{m – y}{m + 1}\)

  • A.
    m = \(\frac{y + k^2}{k^2 + 1}\)
  • B.
    m = \(\frac{y + k^2}{1 – k^2}\)
  • C.
    m = \(\frac{y – k^2}{k^2 + 1}\)
  • D.
    m = \(\frac{y – k^2}{1 – k^2}\)

14.  Find the quadratic equation whose roots are \(\frac{1}{2}\)  and -\(\frac{1}{3}\) 

  • A. 3x\(^2\) + x + 1 = 0
  • B. 6x\(^2\) + x – 1 = 0
  • C. 3x\(^2\) + x – 1 = 0
  • D. 6x\(^2\) – x – 1 = 0

15.   Given that x is directly proportional to y and inversely proportional to Z, x = 15 when y = 10 and Z = 4, find the equation connecting x, y and z

  • A. x = \(\frac{6y}{z}\)
  • B. x = \(\frac{12y}{z}\)
  • C. x = \(\frac{3y}{z}\)
  • D. x = \(\frac{3y}{2z}\)
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