If 4sin2x−3=04sin2x−3=0, find the value of x, when 0° ≤ x ≤ 90°

If 4sin2x−3=04sin2x−3=0, find the value of x, when 0° ≤ x ≤ 90°
A. 90°
B. 45°
C. 60°
D. 30°

Correct Option: Answer is C

Solution:

4sin²x−3=0
4sin2x=3; sin² x= 3/4
sinx=√3/2
∴x=sin−1(√3/2)
x = 60°

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