d/dx[log(4x³–2x)] is equal to

d/dx[log(4x³–2x)] is equal to
A. 12x–2
4x²
B. 43x²–2x
7x

C. 4x²–2
7x +6

D. 12x²–2
4x³ -2x

Correct Option: Answer is B

Solution:
d/dx 〖[log⁡(4x〗^3 -2x)]
Let u = 〖4x〗^3 -2x
d/dx 〖[log⁡(4x〗^3 -2x)] = (d/du)( du/dx)
d/dx (logu)=1/u
du/dx 〖=12x〗^(2 )-2
Therefore, d/dx 〖[log⁡(4x〗^3 -2x)] = (〖12x〗^(2 )-2 )/u
= (〖12x〗^(2 )-2 )/(4x^3- 2x )

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